Question

Каков объём тела ныряльщика, если при его полном погружении на него действует вода с силой 700Н?

Answer 1

На ныряльщика со стороны воды действует сила Архимеда:
FA = pgV, где p-плотность воды ( 1000 кг/м³ - пресная, 1030 кг/м³ -                                                               морская
Если вода пресная то объем тела равен:
V=F/pg=700 / 9,8*1000≈0,07 м³
Ответ: 0,07 м³

Answer 2

Calculating the Volume of the Diver's Body

To calculate the volume of the diver's body when subjected to a force of 700N in water, we can use Archimedes' principle, which states that the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.

The formula to calculate the volume of the diver's body is:

Volume = Force of water / Density of water

Where: - Force of water = 700N (given) - Density of water = 1000 kg/m^3 (standard density of water)

Calculation

Using the given force of water (700N) and the density of water (1000 kg/m^3), we can calculate the volume of the diver's body:

Volume = 700N / 1000 kg/m^3

Volume ≈ 0.7 m^3

Therefore, the volume of the diver's body when subjected to a force of 700N in water is approximately 0.7 cubic meters.