Question

Энергия конденсатора ёмкостью 5мкФ составляет 10 Дж.Определить напряжение на его пластинах.

Answer 1

Дано: W=10 Дж , С=5мкФ=5*10^-6
Найти : U 
Решение : W=CU^2/2 => U=корень из ( 2W/C)= корень из ( 2*10 / 5* 10^-6) = 2000 В

Answer 2

Calculation of Energy in a Capacitor

To determine the voltage across the plates of a capacitor with a capacitance of 5 μF and an energy of 10 J, we can use the formula for the energy stored in a capacitor:

W = (1/2) * C * V^2 Where: - W is the energy stored in the capacitor (given as 10 J) - C is the capacitance of the capacitor (given as 5 μF) - V is the voltage across the plates (to be determined)

Rearranging the formula, we can solve for V:

V = sqrt((2 * W) / C)

Substituting the given values:

V = sqrt((2 * 10 J) / (5 * 10^-6 F))

Simplifying the equation:

V = sqrt(4 * 10^6 V^2)

V = 2 * 10^3 V

Therefore, the voltage across the plates of the capacitor is 2000 V.