Question

Автомобиль трогается с места и движется с постоянным ускорение 5 м/c².Какой путь прошёл автомобиль, если его скорость в конце пути оказалась равно 15 м/c?

Answer 1

v0=0(м/с)

v=v0+at

t=v/a

S=v0*t+(at^2)/2=(at^2)/2=(v^2)/2a

S=(15^2)/(2*5)=22,5(м)

Ответ: 22,5 м

Answer 2

Calculating the Distance Traveled by the Car

To calculate the distance traveled by the car, we can use the following kinematic equation:

v^2 = u^2 + 2as

Where: - v = final velocity (15 m/s) - u = initial velocity (0 m/s, as the car starts from rest) - a = acceleration (5 m/s²) - s = distance traveled (what we want to find)

We can rearrange the equation to solve for s:

s = (v^2 - u^2) / (2a)

Substituting the given values: - v = 15 m/s - u = 0 m/s - a = 5 m/s²

We get: s = (15^2 - 0^2) / (2*5) s = (225 - 0) / 10 s = 225 / 10 s = 22.5 meters

So, the car traveled a distance of 22.5 meters.

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