Question

Відро масою 2 кг опускається на мотузці у криницю. Сила натягу мотузки становить 15 Н. Визначити прискореня руху і вагу відра.

Answer 1

Розв’язок у файлі...............

Answer 2

F = ma , отсюда а = F/m
a = 15/2 = 7.5 м/c^2
P = mg
P = 2*10 = 20 Па

Answer 3

Calculation of Acceleration and Weight

To calculate the acceleration and weight of the bucket, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the force acting on the bucket is the tension in the rope.

Given: - Mass of the bucket (m) = 2 kg - Tension in the rope (F) = 15 N

To find the acceleration (a), we can rearrange Newton's second law equation:

F = m * a

Substituting the given values:

15 N = 2 kg * a

Solving for acceleration (a):

a = 15 N / 2 kg

Using the given values, we can calculate the acceleration of the bucket.

Now, to find the weight of the bucket, we can use the formula:

Weight = mass * acceleration due to gravity

The acceleration due to gravity is approximately 9.8 m/s^2.

Substituting the given values:

Weight = 2 kg * 9.8 m/s^2

Using the given values, we can calculate the weight of the bucket.

Calculation Results

The acceleration of the bucket is approximately 7.5 m/s^2.

The weight of the bucket is approximately 19.6 N.

Please note that these calculations assume that the tension in the rope is the only force acting on the bucket and neglect any air resistance or friction.