Question

Скорый поезд, отходя от станции, движется равноускоренно с ускорением 0,5 м/с2. На каком расстоянии от станции он будет иметь скорость, равную 36 км/ч?

Answer 1

v^2-v0^2=2*a*s

v0=0

s=v^2/2*a

s=10^2/2*0,5=100 м 

Answer 2

Решение:

по формуле находим расстояние:

s=v^2/2*a

s=10^2/2*0,5=100 м

Ответ:100 м .

Answer 3

Calculation of the Distance:

To determine the distance at which the train will have a speed of 36 km/h, we need to use the equation of motion for uniformly accelerated motion:

v^2 = u^2 + 2as

Where: - v is the final velocity (36 km/h) - u is the initial velocity (0 km/h, as the train starts from rest) - a is the acceleration (0.5 m/s^2) - s is the distance traveled

First, let's convert the final velocity from km/h to m/s:

36 km/h = 36 * (1000/3600) m/s = 10 m/s Now, we can rearrange the equation to solve for s:

s = (v^2 - u^2) / (2a)

Substituting the values:

s = (10^2 - 0^2) / (2 * 0.5) = 100 / 1 = 100 m

Therefore, the train will be at a distance of 100 meters from the station when it reaches a speed of 36 km/h.

Answer:

The train will be at a distance of 100 meters from the station when it reaches a speed of 36 km/h.