Question

На паром длиной в 8м и шириной 4м заехал грузовик , в результате чего паром погрузился в воду на 10см. Какова масса грузовика?

Answer 1

10 см=0,1 м
Обьем вытесненной воды = обьему погруж части парома
V=abc=8•4•0,1=3,2 
m=ρV=1000•3,2=3200 кг
Масса груз = массе выт воды
Ответ: 3200 кг=3,2 т

Answer 2

Calculating the Mass of the Truck

To calculate the mass of the truck, we can use the principle of buoyancy. When the truck is on the ferry, it displaces a volume of water equal to its own volume. The weight of this displaced water is equal to the weight of the truck. Given that the ferry has sunk by 10 cm (0.1 m) due to the truck's weight, we can calculate the mass of the truck.

Calculation

The volume of water displaced by the truck can be calculated using the dimensions of the ferry and the depth to which it has sunk.

The volume of water displaced = Length × Width × Depth = 8m × 4m × 0.1m = 3.2 cubic meters

The weight of the water displaced is equal to the weight of the truck. The density of water is approximately 1000 kg/m^3.

So, the mass of the truck can be calculated using the formula: Mass = Volume × Density = 3.2 m^3 × 1000 kg/m^3 = 3200 kg

Therefore, the mass of the truck is 3200 kg.