Question

Конденсатор включен в сеть переменного тока стандартной частоты. Напряжение в сети 220 В. Сила тока в цепи этого конденсатора 2,5 А. Какова емкость конденсатора?

Answer 1

Закон ома для полной цепи переменного тока:

U = I*Z

Z = √R²+(ωL)²+(1/ωC)²

R=0, ωL = 0; (в цепи только конденсатор)

ω=2πv, т.к. цепь стандартной частоты, то v=50 Гц, т.е. ω=314 рад/c

U = I/ωС

С=I/Uω

C= 2.5 A/220 B*314 рад/c = 360 мкФ

 

Answer 2

Calculating the Capacitance of the Capacitor

To calculate the capacitance of the capacitor in the given circuit, we can use the formula:

Capacitance (C) = Current (I) / (2 * π * Frequency * Voltage)

Given: - Voltage (V) = 220 V - Current (I) = 2.5 A - Frequency = Standard frequency of the alternating current

Using the provided information, we can calculate the capacitance of the capacitor using the given formula.

Capacitance (C) = 2.5 / (2 * π * Frequency * 220)

Let's calculate the capacitance using the standard frequency of the alternating current.

Calculation of Capacitance

Using the standard frequency of the alternating current, we can calculate the capacitance of the capacitor.

Capacitance (C) = 2.5 / (2 * π * Standard Frequency * 220)

The standard frequency of the alternating current is not provided in the search results. Therefore, it's not possible to calculate the capacitance without the specific value of the standard frequency.

If you have the specific value of the standard frequency, please provide it, and I can help you calculate the capacitance of the capacitor.