Question

Тележка массой 2 килограмма движущийся со скоростью 3 метров секунду сталкивается с неподвижной тележкой массой 4 килограмма и сцепляется с ней Чему равна скорость тележек после взаимодействия

Answer 1

ПО ЗАКОНУ СОХРАНЕНИЯ ИМПУЛЬСА:
m₁V₁+m₂V₂= (m₁+m₂)V
V= (m₁V₁)/ (m₁+m₂)
V=2*3/(2+4)=6/6=1 м/с 

Answer 2

Calculation of Post-Interaction Velocities

When a trolley with a mass of 2 kilograms and a velocity of 3 meters per second collides with a stationary trolley with a mass of 4 kilograms and becomes coupled with it, the post-interaction velocities of the trolleys can be calculated using the conservation of momentum principle.

According to the conservation of momentum principle, the sum of the initial momenta of the two trolleys is equal to the sum of their final momenta.

Using the formula V = m1 * V1 / (m1 + m2), where: - V is the final velocity of the coupled trolleys - m1 and m2 are the masses of the individual trolleys - V1 is the initial velocity of the first trolley

Substituting the given values: - m1 = 2 kg - V1 = 3 m/s - m2 = 4 kg

The final velocity V of the coupled trolleys can be calculated as follows: V = 2 * 3 / (2 + 4) = 1 m/s.

Therefore, the velocity of the trolleys after the interaction is 1 meter per second.