Question

Жесткость прорезиненного жгута 7,2 * 10⁴ Н/м. На какую длину растянется жгут, если на него действует сила 10 кН? Стальная пружина под действием силы 245 Н удлинилась 35 мм. Определите жесткость пружины.

Answer 1

вот вроде как-то так........................................

Answer 2

Calculation of the Elongation of the Rubberized Cord

To calculate the elongation of the rubberized cord, we can use Hooke's Law, which states that the elongation of an elastic material is directly proportional to the applied force. Hooke's Law can be expressed as:

F = k * ΔL

Where: - F is the applied force (in newtons, N) - k is the stiffness or spring constant (in newtons per meter, N/m) - ΔL is the change in length (in meters, m)

In this case, we are given that the stiffness of the rubberized cord is 7.2 * 10^4 N/m and the applied force is 10 kN (10,000 N). We need to find the change in length (ΔL).

Let's rearrange the equation to solve for ΔL:

ΔL = F / k

Substituting the given values:

ΔL = 10,000 N / (7.2 * 10^4 N/m)

Calculating the result:

ΔL ≈ 0.1389 meters

Therefore, the rubberized cord will elongate by approximately 0.1389 meters when a force of 10 kN is applied to it.

Calculation of the Stiffness of the Steel Spring

To calculate the stiffness of the steel spring, we can use Hooke's Law again. In this case, we are given that the force applied to the spring is 245 N and the elongation is 35 mm (0.035 m).

Let's rearrange the equation to solve for the stiffness (k):

F = k * ΔL

Substituting the given values:

245 N = k * 0.035 m

Solving for k:

k = 245 N / 0.035 m

Calculating the result:

k ≈ 7000 N/m

Therefore, the stiffness of the steel spring is approximately 7000 N/m.