Question

ФИЗИКА!! СРЧОНОО Грузик на пружине за 12 с совершил 28 колебаний. Определи период колебаний грузика. Среди предложенных ответов выбери и отметь ответ, наиболее близкий к правильному.

Answer 1

Каждые 2.4 секунд совершает 1 колебание грузик

Answer 2

Calculation of the Period of Oscillation

To determine the period of oscillation of the weight on the spring, we can use the formula:

T = 2π√(m/k)

where: - T is the period of oscillation, - π is a mathematical constant approximately equal to 3.14159, - m is the mass of the weight, and - k is the spring constant.

In this case, we are given that the weight completed 28 oscillations in 12 seconds. To find the period, we need to divide the total time by the number of oscillations:

T = 12 s / 28 oscillations

Let's calculate the period using this information.

Calculation

To find the period, we divide the total time by the number of oscillations:

T = 12 s / 28 oscillations

Calculating this, we get:

T ≈ 0.4286 s

Therefore, the period of oscillation of the weight on the spring is approximately 0.4286 seconds.

Please note that the provided search result snippet does not contain any relevant information for this specific question. However, the calculation provided above is based on the standard formula for the period of oscillation and the given information about the number of oscillations and the time taken.