Question

Тело брошено вертикально вверх с высоты 20 м с начальной скоростью 3 м/с. На какой высоте окажется тело через 2 с после начала движения?

Answer 1

H=h0+uot-gt^2/2

H=20+6-10*4/2

H=6 метров

Answer 2

Calculation of the Height of the Object

To determine the height at which the object will be after 2 seconds, we can use the equations of motion for vertical motion under constant acceleration. The equation we will use is:

h = h0 + v0t + (1/2)gt^2

Where: - h is the final height - h0 is the initial height (20 m in this case) - v0 is the initial velocity (3 m/s in this case) - t is the time (2 s in this case) - g is the acceleration due to gravity (approximately 9.8 m/s^2)

Plugging in the values, we get:

h = 20 + (3 * 2) + (1/2) * 9.8 * (2^2)

Simplifying the equation, we get:

h = 20 + 6 + 19.6

h = 45.6

Therefore, the object will be at a height of 45.6 meters after 2 seconds.

Conclusion

After 2 seconds, the object will reach a height of 45.6 meters.