Question

В воздухе длина волны 680нм, в стекле 453нм. Под каким углом свет падает на плоскую границу раздела воздух-стекло, если отраженный и преломленный лучи образуют прямой угол

Answer 1

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Answer 2

Calculating the Angle of Incidence for Light Passing from Air to Glass

To calculate the angle of incidence for light passing from air to glass, we can use Snell's Law, which relates the angles of incidence and refraction to the refractive indices of the two media. The formula for Snell's Law is:

n1 * sin(θ1) = n2 * sin(θ2)

Where: - n1 = refractive index of the initial medium (in this case, air) - θ1 = angle of incidence - n2 = refractive index of the second medium (in this case, glass) - θ2 = angle of refraction

We are given the wavelength of light in air (680 nm) and in glass (453 nm). The refractive index of a medium is related to the speed of light in that medium, and the speed of light is inversely proportional to the wavelength. Therefore, we can use the relationship between refractive index and wavelength to find the refractive indices of air and glass at these wavelengths.

Finding the Refractive Indices

The refractive index of a medium can be calculated using the formula:

n = c / v

Where: - n = refractive index - c = speed of light in a vacuum - v = speed of light in the medium

Using the given wavelengths and the speed of light in a vacuum (approximately 3.00 x 10^8 m/s), we can calculate the speeds of light in air and glass at these wavelengths and then find the refractive indices.

Calculating the Angle of Incidence

Once we have the refractive indices of air and glass at the given wavelengths, we can use Snell's Law to calculate the angle of incidence for light passing from air to glass, given that the reflected and refracted rays form a right angle.

I will now calculate the refractive indices and the angle of incidence using the provided information.