Question

Поезд отходя от станции движется равноускоренно с ускорением 0.2 м/с2. какой путь пройдёт он за 20 с?

Answer 1

Дано:
a=0,2м/c2
t=20с
V0=0м/с
найти
s=?
s=V0+/at2/
             2
S=0+0,2*400c2
              2
=40м

Answer 2

Calculating the Distance Traveled by the Train

The distance traveled by a train moving with constant acceleration can be calculated using the equation:

distance = initial velocity * time + (1/2) * acceleration * time^2

Given: - Initial velocity (u) = 0 m/s (since the train is starting from rest) - Acceleration (a) = 0.2 m/s^2 - Time (t) = 20 s

Using the above equation, we can calculate the distance traveled by the train.

distance = (0 * 20) + (1/2) * 0.2 * 20^2

distance = 0 + 0.5 * 0.2 * 400

distance = 0 + 40

distance = 40 meters

Therefore, the train will travel a distance of 40 meters in 20 seconds.