Question

Молекула азота при нормальных условиях движется со скоростью 454 м.с.Определите импульс молекулы

Answer 1

Молекула азота при нормальных условиях движется со скоростью 454 м.с.Определите импульс молекулы

скорость молекулы v=454 м/с

масса молекулы азота  m0=M/Na=14*10^-3/6*10^23=(14/6)* 10^-26 кг 

число Авогадро Na=6*10^23

молярная масса М=14*10^-3 кг/моль

импульс молекулы p=m0*V= (14/6)* 10^-26* 454 =1059,(3) *10^-26= 1,06 *10^-23 кг*м/с

 

Ответ 1,06 *10^-23 кг*м/с

Answer 2

Calculating the Impulse of a Nitrogen Molecule

To calculate the impulse of a nitrogen molecule, we can use the formula:

Impulse = Force × Time

However, since we are given the speed of the nitrogen molecule, we can also calculate the impulse using the formula:

Impulse = Mass × Change in Velocity

Given: - Speed of the nitrogen molecule, v = 454 m/s - Mass of a nitrogen molecule, m = 28.02 g/mol

First, we need to convert the mass from grams per mole to kilograms: - 1 g = 0.001 kg - 1 mol = Avogadro's number = 6.022 × 10^23 molecules

So, the mass of a single nitrogen molecule, m = 28.02 g/mol = 28.02 × 10^-3 kg/mol

Now, we can calculate the impulse using the formula: Impulse = Mass × Change in Velocity

Impulse = m × Δv

Where Δv is the change in velocity, which is the final velocity minus the initial velocity. Since the molecule is moving at a constant speed, the change in velocity is simply the speed of the molecule, v.

Impulse = m × v

Let's calculate the impulse using the given speed and mass of the nitrogen molecule.

Impulse = 28.02 × 10^-3 kg/mol × 454 m/s

Impulse = 0.02802 kg/mol × 454 m/s

Impulse ≈ 12.73 kg m/s

So, the impulse of the nitrogen molecule at the given speed is approximately 12.73 kg m/s.