Question

Летящий снаряд разорвался на два осколка с одинаковыми массами . модули скоростей осколков v1 =300 м/с и v2=400 м/с, а угол между векторами скоростей осколков равен 90 градусов. найти модуль скорости v0 снаряда до разрыва .

Answer 1

Так как импульсы направлены под углом 90 градусов,то
Р=корень из P1^2+P2^2=2m*V2*m-потому что два осколка равной массы
после сокращения массы получаем
V=(корень из V1^2+ V2^2)/2 =500/2=250 м/с.

Answer 2

Calculation of the Projectile's Velocity Before the Explosion

To find the velocity of the projectile before the explosion, we can use the principle of conservation of momentum. According to this principle, the total momentum before the explosion is equal to the total momentum after the explosion.

Let's denote the mass of each fragment as m1 and m2, and the velocities of the fragments as v1 and v2, respectively. The angle between the velocity vectors of the fragments is given as 90 degrees.

Using the conservation of momentum, we can write the equation:

m1 * v1 + m2 * v2 = (m1 + m2) * v0

where v0 is the velocity of the projectile before the explosion.

Since the masses of the fragments are equal (m1 = m2), we can simplify the equation to:

2 * m * v1 = 2 * m * v0

where m is the mass of each fragment.

Simplifying further, we get:

v1 = v0

Therefore, the velocity of the projectile before the explosion is equal to the velocity of one of the fragments, which is v1.

Now, let's substitute the given values into the equation to find the velocity of the projectile before the explosion.

Given: v1 = 300 m/s v2 = 400 m/s

Using the equation v1 = v0, we can conclude that the velocity of the projectile before the explosion is 300 m/s.