Question

На участке электрической цепи последовательно соединены лампочка и резистор . Сопротивление лампочки (R=12 Ом) , а сопротивление резистора (R=72 Ом ) .Определите напряжение на резисторе (U -?) , если напряжение на лампочке U=2,5B

Answer 1

Решение:
1) I=R/U=2.5/12=0.2 (примерно)
2)U=IR=0.2A*72Om=14.4 В
Ответ: 14,4 В

Answer 2

Calculating Voltage on the Resistor in a Series Circuit

In a series circuit, the same current flows through all components. Using this information, we can calculate the voltage on the resistor using the given values.

Given: - Resistance of the lamp (R_lamp) = 12 Ω - Resistance of the resistor (R_resistor) = 72 Ω - Voltage across the lamp (U_lamp) = 2.5 V

Calculating Current in the Circuit

First, we can calculate the current in the circuit using the voltage across the lamp and its resistance.

The formula to calculate current (I) is given by Ohm's law: I = U / R, where U is the voltage and R is the resistance.

So, the current in the circuit (I) can be calculated as: I = U_lamp / R_lamp

Calculating Voltage on the Resistor

Since the same current flows through all components in a series circuit, the voltage across the resistor (U_resistor) can be calculated using Ohm's law: U = I * R, where I is the current and R is the resistance.

So, the voltage across the resistor (U_resistor) can be calculated as: U_resistor = I * R_resistor

Calculations

Let's perform the calculations using the given values: - I = U_lamp / R_lamp = 2.5 V / 12 Ω - U_resistor = I * R_resistor

Result

By performing the calculations, we can determine the voltage on the resistor (U_resistor).