Question

Согласно показаниям счетчика в помещении в течении месяца (30 дней) было израсходованно 50кВт*ч электроэнергии. ток какой величины протекал по цепи при вкл потребителях, если ежедневно они были вкл в среднем по 8 часов одновременно? напряжение в цепи 220 В

Answer 1

Работа тока за сутки:
A1 = J*U*t = J*220*8 = J*1760 Вт*ч = J*1,76 кВт*ч
Работа за 30 дней:
A = 30*J*1,76=52,8*J кВ*ч 
50 = 52,8*J
Сила тока:
J = 50/52,8 ≈0,95 A

Answer 2

Calculation of Current

To calculate the current flowing through the circuit, we can use Ohm's Law, which states that the current (I) is equal to the voltage (V) divided by the resistance (R). In this case, the voltage is 220 V, and we need to find the resistance.

To find the resistance, we can use the formula: Resistance (R) = Energy (E) / (Voltage (V) * Time (t)).

Given that the energy consumed over 30 days is 50 kWh (kilowatt-hours) and the voltage is 220 V, we can calculate the resistance as follows:

Resistance (R) = 50 kWh / (220 V * 30 days)

Now, let's convert the energy from kilowatt-hours to watt-hours:

50 kWh = 50,000 watt-hours

Substituting the values into the formula:

Resistance (R) = 50,000 watt-hours / (220 V * 30 days)

To calculate the current, we need to convert the time from days to hours. Since each day the devices are turned on for 8 hours, over 30 days, they are turned on for a total of 240 hours.

Resistance (R) = 50,000 watt-hours / (220 V * 240 hours)

Now, let's calculate the resistance:

Resistance (R) = 50,000 watt-hours / (220 V * 240 hours) = 0.947 ohms

Finally, we can calculate the current (I) using Ohm's Law:

Current (I) = Voltage (V) / Resistance (R) = 220 V / 0.947 ohms

Therefore, the current flowing through the circuit when the devices are turned on for 8 hours daily is approximately 232.3 Amperes.

Please note that this calculation assumes a purely resistive load and does not take into account any other factors that may affect the circuit's behavior.