Question

С каким ускорением движется протон в однородном электростатическом поле напряженностью 10 кВ/м?Масса протона 1,67*10^-27,заряд 1,6*40^-19

Answer 1

Решим задачу по второму закону ньютона
ma = Fe
a = Fe/m
Fe = Eq
a = Eq/m = $\frac{10^4 *1.6*10^-^1^9}{1.67*10^-^2^7}$ м\с^2

Answer 2

Calculation of the Acceleration of a Proton in an Electric Field

To calculate the acceleration of a proton in a uniform electric field, we can use the equation:

a = F/m

where: - a is the acceleration of the proton, - F is the force experienced by the proton in the electric field, and - m is the mass of the proton.

The force experienced by the proton in an electric field can be calculated using the equation:

F = qE

where: - F is the force experienced by the proton, - q is the charge of the proton, and - E is the electric field strength.

Given the following values: - Charge of the proton (q) = 1.6 x 10^-19 C- Electric field strength (E) = 10 kV/m = 10,000 V/m

We can calculate the force experienced by the proton:

F = (1.6 x 10^-19 C) x (10,000 V/m)

Now, we can substitute the force value into the acceleration equation:

a = F / m

Substituting the values: - Mass of the proton (m) = 1.67 x 10^-27 kg We can calculate the acceleration of the proton in the electric field.

Please note that the above calculations are based on the given values and assumptions. Let's calculate the acceleration:

F = (1.6 x 10^-19 C) x (10,000 V/m) = 1.6 x 10^-15 N

a = (1.6 x 10^-15 N) / (1.67 x 10^-27 kg) = 9.58 x 10^11 m/s^2

Therefore, the acceleration of the proton in the given electric field is approximately 9.58 x 10^11 m/s^2.

Please let me know if there is anything else I can help you with!