Question

1)танк массой 1000n кг движется n метров в секунду и производит выстрел в направлении движения со скоростью 100n метров в секунду. какую скорость будет иметь танк в первую секунду после выстрела. масса снаряда n кг.. помогите решить срочно!!

Answer 1

Дано V1=n    m1=1000 n      m2=n    V2=100n    U-?


если выстрел произведен в направлении движения


m1*V1=m2V2+m1*U

U=V1-m2V2\m1=n-n*100n\1000n=n-0,1n=0,9n ответ


если выстрел произведен против движения

m1V1= m1*U-m2V2

U=V1+m2V2\\m1=1,1 -ответ

Answer 2

Calculation of Tank's Velocity after Firing

To calculate the velocity of the tank after firing, we need to consider the conservation of momentum. The momentum before firing is equal to the momentum after firing.

The momentum of an object is given by the product of its mass and velocity. Let's denote the mass of the tank as M (given as 1000n kg), the initial velocity of the tank as V (given as n m/s), the mass of the projectile as m (given as n kg), and the velocity of the projectile as v (given as 100n m/s).

Before firing, the total momentum is the sum of the momentum of the tank and the momentum of the projectile:

M * V + m * 0 = (M + m) * V'

After firing, the total momentum is the sum of the momentum of the tank (which is now moving at a new velocity V') and the momentum of the projectile:

(M + m) * V' + m * v = 0

Simplifying the equations, we can solve for V':

M * V = (M + m) * V' - m * v

V' = (M * V + m * v) / (M + m)

Now we can substitute the given values into the equation and calculate the velocity of the tank after firing:

V' = (1000n * n + n * 100n) / (1000n + n)

Let's simplify this expression:

V' = (1000n^2 + 100n^2) / (1000n + n)

V' = (1100n^2) / (1001n)

Simplifying further:

V' = 1.098 n m/s

Therefore, the velocity of the tank in the first second after firing will be 1.098n m/s.

Please note that this calculation assumes an idealized scenario without considering factors such as air resistance, friction, or recoil.