Question

Шар начинает двигаться по наклонной плоскости вверх с начальной скоростью 10м/с и ускорением 2м/с.Какой путь пройдет шар до остановки?

Answer 1

$S= \frac{v^2- x_{0} ^2}{2a}$

v0=0 m/s Потому что тело в итоге останавливается 

Подставив получим 25 м

Answer 2

Calculation of the Distance Traveled by the Ball

To calculate the distance traveled by the ball before coming to a stop, we can use the equations of motion. The given information includes the initial velocity (10 m/s) and the acceleration (2 m/s²) of the ball. We need to find the distance traveled.

Using the equation of motion s = ut + (1/2)at², where: - s is the distance traveled, - u is the initial velocity, - t is the time taken, and - a is the acceleration,

we can substitute the given values and solve for s.

Given: - Initial velocity (u) = 10 m/s - Acceleration (a) = 2 m/s²

We need to find the distance traveled (s).

Solution:

Using the equation s = ut + (1/2)at², we can substitute the given values:

s = (10 m/s)(t) + (1/2)(2 m/s²)(t²)

To find the time taken (t), we can use the equation v = u + at, where: - v is the final velocity, - u is the initial velocity, - a is the acceleration, and - t is the time taken.

Given: - Initial velocity (u) = 10 m/s - Acceleration (a) = 2 m/s² - Final velocity (v) = 0 m/s (since the ball comes to a stop)

Using the equation v = u + at, we can substitute the given values:

0 m/s = 10 m/s + (2 m/s²)(t)

Solving for t:

10 m/s + (2 m/s²)(t) = 0 m/s

(2 m/s²)(t) = -10 m/s

t = -10 m/s / 2 m/s²

t = -5 s

Since time cannot be negative in this context, we can discard the negative value and consider the time taken as t = 5 s.

Now, substituting the value of t back into the equation s = ut + (1/2)at²:

s = (10 m/s)(5 s) + (1/2)(2 m/s²)(5 s)²

s = 50 m + (1/2)(2 m/s²)(25 s²)

s = 50 m + (1/2)(2 m/s²)(625 s²)

s = 50 m + (1/2)(1250 m/s²)

s = 50 m + 625 m

s = 675 m

Therefore, the ball will travel a distance of 675 meters before coming to a stop.