Question

Тело брошено вертикально вверх со скоростью 30 м/c за какое время тело пройдет путь равный 50 м?

Answer 1

Определим мах. высоту подъема
h(max)=v0^2 / 2g.
h(max)=900 / 2*10=45м. Значим оно поднялось на высоту 45м, а потом ещё 5м падало . ( 45+5)=50м. Определим время подъёма
h(max)=g*t1^2 / 2.
t1= квадратный корень  из 2h(max) / g.
t1.=кор.кв.из 2*45 / 10=3c. а тперь теперь время падения
h2=g*t2^2 / 2.
t2=кор.кв.из 2*h2 / g.
t2=кор.кв.из 2*5 / 10=1c.
общее время = сумме.
t=t1+t2.
t=3c + 1c=4c.

Answer 2

Calculation of Time Taken by the Body

To calculate the time taken by the body to cover a distance of 50 m when thrown vertically upwards with an initial velocity of 30 m/s, we can use the equation of motion:

S = ut + (1/2)at^2

Where: - S is the distance covered (50 m in this case) - u is the initial velocity (30 m/s in this case) - a is the acceleration (which is equal to the acceleration due to gravity, approximately 9.8 m/s^2) - t is the time taken

Plugging in the given values, we can solve for t:

50 = (30)t + (1/2)(-9.8)t^2

Simplifying the equation, we get a quadratic equation:

-4.9t^2 + 30t - 50 = 0

To solve this quadratic equation, we can use the quadratic formula:

t = (-b ± √(b^2 - 4ac)) / (2a)

In this case, a = -4.9, b = 30, and c = -50. Plugging in these values, we can calculate the time taken by the body.

Let's calculate the time taken using the quadratic formula.