Question

Тело брошено горизонтально со скоростью 5 м/с.Дальность полета тебе 10м.Сколько времени падало тело? С какой высоты падало тело? С какой скоростю ударилось тело о землю ?

Answer 1

S=Vx*t
t=S/Vx=10/5=2 c
h=g*t^2/2=10*2^2/2=20 м
Vy=g*t=10*2=20 м

Answer 2

Calculation of Time of Fall, Height, and Impact Velocity

To calculate the time of fall, height, and impact velocity of an object thrown horizontally with an initial velocity of 5 m/s and a range of 10 m, we can use the equations of motion.

Let's assume that the object is in free fall and neglect air resistance.

Time of Fall: The time of fall can be calculated using the equation: *t = d / v* where: - *t* is the time of fall, - *d* is the range or distance traveled by the object, and - *v* is the horizontal velocity of the object.

Substituting the given values, we have: *t = 10 m / 5 m/s = 2 seconds*.

Height: The height from which the object falls can be calculated using the equation: *h = (1/2) * g * t^2* where: - *h* is the height, - *g* is the acceleration due to gravity (approximately 9.8 m/s^2), and - *t* is the time of fall.

Substituting the given values, we have: *h = (1/2) * 9.8 m/s^2 * (2 s)^2 = 19.6 m*.

Impact Velocity: The impact velocity can be calculated using the equation: *v_impact = v_horizontal = 5 m/s* where: - *v_impact* is the impact velocity, and - *v_horizontal* is the horizontal velocity of the object.

Therefore, the impact velocity of the object when it hits the ground is 5 m/s.

To summarize: - The time of fall is 2 seconds. - The height from which the object falls is 19.6 meters. - The impact velocity of the object when it hits the ground is 5 m/s.

Please note that these calculations assume ideal conditions and neglect factors such as air resistance.