Question

ПОМОГИТЕ ПОЖАЛУЙСТА!!!Снарял вылетел из дула орудия под углом 30 градусов к горозонту со скоростью 600м/с. Через сколько времени будет находиться снаряд на высоте 400м? какова скорость снаряа в высшей точке траектории? сопротивление воздуха не учитывать.ПОООМОГИТЕ!!!

Answer 1

ПОМОГИТЕ ПОЖАЛУЙСТА!!!
Снарял вылетел из дула орудия под углом 30 градусов к горозонту со скоростью 600м/с. Через сколько времени будет находиться снаряд на высоте 400м? какова скорость снаряа в высшей точке траектории? сопротивление воздуха не учитывать.
ПОООМОГИТЕ!!!
Проецируем начальную скорость на ось y. V0y=V0*sinA V0y=600*1/2=300 м/c
S=v0t-at^2/2 400=300t-4,905t^2
Решаем квадратное уравнение. 
4,905t^2-300t+400=0 
t1=300-286.62/9.81=1.36 секунды.
t2 нам не нужен, там слишком большое время.
А в высшей точке траектории скорость снаряда равна 0. На то она и высшая.

Answer 2

Calculation of Time and Velocity of Projectile

To calculate the time it takes for the projectile to reach a height of 400m and the velocity of the projectile at the highest point of its trajectory, we can use the equations of projectile motion.

The time it takes for the projectile to reach a certain height can be calculated using the equation:

t = (2 * u * sin(theta)) / g Where: - t is the time taken - u is the initial velocity of the projectile (600m/s in this case) - theta is the angle of projection (30 degrees in this case) - g is the acceleration due to gravity (approximately 9.8m/s^2)

Substituting the given values into the equation, we can calculate the time taken for the projectile to reach a height of 400m.

t = (2 * 600 * sin(30)) / 9.8

Calculating this expression gives us the value of t.

To find the velocity of the projectile at the highest point of its trajectory, we can use the equation:

v = u * cos(theta) Where: - v is the velocity at the highest point - u is the initial velocity of the projectile (600m/s in this case) - theta is the angle of projection (30 degrees in this case)

Substituting the given values into the equation, we can calculate the velocity of the projectile at the highest point.

v = 600 * cos(30)

Calculating this expression gives us the value of v.

Let's calculate the values using the given information.

Calculation:

Using the equations mentioned above, we can calculate the time it takes for the projectile to reach a height of 400m and the velocity of the projectile at the highest point of its trajectory.

Given: - Initial velocity (u) = 600m/s - Angle of projection (theta) = 30 degrees - Height (h) = 400m - Acceleration due to gravity (g) = 9.8m/s^2

Using the equation t = (2 * u * sin(theta)) / g, we can calculate the time taken:

t = (2 * 600 * sin(30)) / 9.8

Calculating this expression gives us the value of t.

Using the equation v = u * cos(theta), we can calculate the velocity at the highest point:

v = 600 * cos(30)

Calculating this expression gives us the value of v.

Let's calculate the values:

t = (2 * 600 * sin(30)) / 9.8 = 38.78 seconds (approximately)

v = 600 * cos(30) = 519.62 m/s (approximately)

Therefore, the projectile will take approximately 38.78 seconds to reach a height of 400m, and its velocity at the highest point of its trajectory will be approximately 519.62 m/s.

Please note that these calculations do not take into account air resistance, as specified in the question.