Question

Два резистора сопротивлением 10 Ом и 50 Ом соединены параллельно. Сила тока во втором резисторе 0,4А. Каково напряжение в цепи?

Answer 1

U = R * I 

R - сопротивление 
I - сила тока ( 0,4 A ( во втором резисторе тоже 0,4 A , так как в параллельном соединении сила тока везде одинакова!) )

R общ = 1/R1 + 1/R2 = 1/10 + 1/50 = 0,1 + 0,02 = 0,12 

U = 0,12 * 0,4 = 0,048 B 

Answer 2

Так, сперва находим силу тока во втором резисторе. так как они соединены параллельно то у них одинаковое напряжение. после того как найдем силу тока, найдем общее сопротивление в резисторах. после этого найдем по закону Ома напряжение в цепи.

Answer 3

Calculation of Voltage in the Circuit

To find the voltage in the circuit, we can use Ohm's Law, which states that the voltage (V) is equal to the current (I) multiplied by the resistance (R). In this case, we know the current in the second resistor (I2) is 0.4A, and we need to find the voltage in the circuit.

Let's assume the voltage in the circuit is V.

Using Ohm's Law, we can write the equation:

V = I2 * R2

Where: - V is the voltage in the circuit (to be determined) - I2 is the current in the second resistor (0.4A) - R2 is the resistance of the second resistor (50Ω)

Substituting the given values into the equation, we get:

V = 0.4A * 50Ω

Calculating the expression, we find:

V = 20V

Therefore, the voltage in the circuit is 20 volts.

Please note that the sources provided do not directly answer the question. However, the calculation is based on the fundamental principles of Ohm's Law, which is a well-established concept in electrical engineering.