Question

Найти напряженность поля диполя с электрическим моментом 0.8 нКл * м на расстоянии 37 см от центра диполя в перпендикулярном направлении

Answer 1

E=2*p/(4*п*e*r^3)=2*0.8*10^-9/(4*3.14*8.85*10^-12*0.37^3)=  284 В/м

Answer 2

Finding the Electric Field Intensity of a Dipole

To find the electric field intensity of a dipole at a distance of 37 cm from its center in a perpendicular direction, we can use the formula:

E = (1 / 4πε₀) * (2p / r³)

Where: - E is the electric field intensity - π is a mathematical constant approximately equal to 3.14159 - ε₀ is the permittivity of free space, which is approximately equal to 8.854 x 10⁻¹² C²/Nm² - p is the electric dipole moment - r is the distance from the center of the dipole

Given that the electric dipole moment is 0.8 nC*m and the distance from the center of the dipole is 37 cm (or 0.37 m), we can substitute these values into the formula to find the electric field intensity.

E = (1 / 4πε₀) * (2 * 0.8 nC*m / (0.37 m)³)

Let's calculate the value of the electric field intensity using the given values:

E = (1 / 4π * 8.854 x 10⁻¹² C²/Nm²) * (2 * 0.8 x 10⁻⁹ C*m / (0.37 m)³)

Calculating this expression will give us the electric field intensity of the dipole at a distance of 37 cm from its center in a perpendicular direction.