Question

Мяч, массой 100 г, летящий со скоростью 1.5 м/с пойман на лету. Какой средней силой мяч действует на руку, если его скорость уменьшается до нуля за время,равное 0.03 с?

Answer 1

mv=Ft

F=mv/t=(0.1kg*1.5m/s)/0.03s=5N

Answer 2

This is a physics question that requires some calculations and knowledge of Newton's laws of motion. I will try to answer it in detail using the information from the web search results.

The question is: A ball with a mass of 100 g, flying at a speed of 1.5 m/s, is caught in flight. What average force does the ball exert on the hand, if its speed decreases to zero in a time equal to 0.03 s?

To answer this question, we need to find the acceleration of the ball and the force that the hand applies to the ball. According to Newton's second law of motion, the force is equal to the product of the mass and the acceleration: F = ma. The acceleration is the rate of change of the velocity: a = (V - V0) / t, where V is the final velocity, V0 is the initial velocity, and t is the time interval.

Since the ball is caught in flight, its final velocity is zero: V = 0 m/s. The initial velocity is given as 1.5 m/s: V0 = 1.5 m/s. The time interval is also given as 0.03 s: t = 0.03 s. Therefore, we can plug these values into the formula for acceleration and get:

a = (V - V0) / t a = (0 - 1.5) / 0.03 a = -50 m/s^2

The negative sign indicates that the acceleration is opposite to the direction of the initial velocity, which means that the ball is slowing down.

Now we can use the formula for force and the mass of the ball, which is 100 g or 0.1 kg, to find the force that the hand applies to the ball:

F = ma F = 0.1 * (-50) F = -5 N

The negative sign indicates that the force is opposite to the direction of the acceleration, which means that the force is in the same direction as the initial velocity. This makes sense, because the hand is pushing the ball back to stop it.

According to Newton's third law of motion, for every action there is an equal and opposite reaction. This means that the force that the ball exerts on the hand is equal in magnitude but opposite in direction to the force that the hand exerts on the ball. Therefore, the answer to the question is:

The ball exerts a force of 5 N on the hand.

This answer is consistent with the answer given by Алла on Uchi.ru. I hope this explanation was helpful and clear. If you have any more questions, feel free to ask me.