Question

Тепловоз,двигаясь равноускорено из состояния покоя с ускорением 0,1 м/с2,увеличивает скорость до 80 км/ч.за какое время эты скорость достигнута?какой путь за это время пройден?

Answer 1

Скорость V=a*t     t=V:a=22,2м\с :0,1м\с в квадрате =222 с    ПутьS=a*t в квадрате :2= 0,1м\с2 *49284 \2=2464м

Answer 2

Problem Analysis

We are given the following information: - A locomotive is moving with a constant acceleration of 0.1 m/s^2. - The locomotive increases its speed to 80 km/h.

We need to find: 1. The time it takes for the locomotive to reach this speed. 2. The distance traveled by the locomotive during this time.

Solution

To solve this problem, we can use the equations of motion. The equation that relates acceleration, initial velocity, final velocity, and time is:

v = u + at

where: - v is the final velocity - u is the initial velocity - a is the acceleration - t is the time

We can rearrange this equation to solve for time:

t = (v - u) / a

Let's substitute the given values into this equation and calculate the time it takes for the locomotive to reach a speed of 80 km/h.

Calculation

Given: - Acceleration (a) = 0.1 m/s^2 - Initial velocity (u) = 0 m/s - Final velocity (v) = 80 km/h = 80 * (1000/3600) m/s

Substituting these values into the equation, we get:

t = (80 * (1000/3600) - 0) / 0.1

Now, let's calculate the time.

Time Calculation

t = (80 * (1000/3600) - 0) / 0.1

Simplifying the equation:

t = (80 * 1000) / (3600 * 0.1)

t = (80000) / (360)

t ≈ 222.22 seconds

Therefore, it takes approximately 222.22 seconds for the locomotive to reach a speed of 80 km/h.

Distance Calculation

To calculate the distance traveled by the locomotive during this time, we can use the equation:

s = ut + (1/2)at^2

where: - s is the distance traveled - u is the initial velocity - a is the acceleration - t is the time

Given: - Initial velocity (u) = 0 m/s - Acceleration (a) = 0.1 m/s^2 - Time (t) = 222.22 seconds

Substituting these values into the equation, we get:

s = 0 * 222.22 + (1/2) * 0.1 * (222.22)^2

Now, let's calculate the distance.

Distance Calculation

s = 0 * 222.22 + (1/2) * 0.1 * (222.22)^2

Simplifying the equation:

s = 0 + (1/2) * 0.1 * (222.22)^2

s = (1/2) * 0.1 * (222.22)^2

s ≈ 247.25 meters

Therefore, the locomotive travels approximately 247.25 meters during this time.

Answer

The locomotive takes approximately 222.22 seconds to reach a speed of 80 km/h, and it travels approximately 247.25 meters during this time.