Question

Внутренняя энергия газа увеличилась на 29 Дж при подведении к нему 44 Дж тепла. Определите работу совершенную над газом

Answer 1

ΔU=29 Дж
Q= 44 Дж
A-?  


ΔU=Q+A,
A=ΔU-Q,
A= 29-44=-15 Дж.

Answer 2

Calculation of Work Done on the Gas

To determine the work done on the gas, we need to use the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system:

ΔU = Q - W

Where: - ΔU is the change in internal energy of the gas - Q is the heat added to the gas - W is the work done by the gas

In this case, the internal energy of the gas increased by 29 J when 44 J of heat was added to it. We need to find the work done by the gas.

Let's substitute the given values into the equation:

29 J = 44 J - W

To find the value of W, we rearrange the equation:

W = 44 J - 29 J

Calculating the expression:

W = 15 J

Therefore, the work done on the gas is 15 J.