Question

Резистори, опори яких 30 і 60 Ом, з'єднані послідовно й підключені до батарейки.Напруга га першому резисторі 3 В.Яка напруга на другому резисторі?

Answer 1

I₁=U₁/R₁=3/30=0.1 (A)
I₂=I₁
U₂=I₂•R₂=0.1•60=6 (B)

Answer 2

Calculation of Voltage on the Second Resistor

To calculate the voltage on the second resistor, we need to consider the resistances and the voltage across the first resistor.

Given: - Resistance of the first resistor (R1): 30 Ω - Resistance of the second resistor (R2): 60 Ω - Voltage across the first resistor (V1): 3 V

We can use Ohm's Law to calculate the current flowing through the circuit:

Ohm's Law: V = I * R

Where: - V is the voltage across the resistor - I is the current flowing through the resistor - R is the resistance of the resistor

Since the resistors are connected in series, the current flowing through both resistors will be the same. Let's assume the current flowing through the circuit is I.

Using Ohm's Law for the first resistor: V1 = I * R1

Solving for I: I = V1 / R1

Now, we can use the current (I) to calculate the voltage across the second resistor (V2) using Ohm's Law for the second resistor: V2 = I * R2

Substituting the value of I: V2 = (V1 / R1) * R2

Now, let's substitute the given values into the equation and calculate the voltage on the second resistor.

Calculation: V1 = 3 V R1 = 30 Ω R2 = 60 Ω

V2 = (V1 / R1) * R2 = (3 V / 30 Ω) * 60 Ω = 6 V

Therefore, the voltage on the second resistor is 6 V.