Question

Чему равна архимедова сила действующая в воде на тело объемом на 125 см3 из стекла, алюминия ,свинца?

Answer 1

Архимедова сила
F= po g V
F= 1000×10× 125× 10^-6=1, 25 H
тк объемы тел одинаковые и они все находятся в воде , значит и Архимедова сила будет у каждого тела одна и таже
Ответ 1, 25 Н у стекла, алюминия , свинца

Answer 2

Calculating Archimedes' Force in Water

To calculate the Archimedes' force acting on an object in water, we can use the formula:

F = ρ * V * g

Where: - F is the Archimedes' force, - ρ is the density of the fluid (in this case, water), - V is the volume of the object submerged in the fluid, and - g is the acceleration due to gravity.

Calculating the Archimedes' Force for Different Materials

Let's calculate the Archimedes' force for objects of volume 125 cm³ made of glass, aluminum, and lead.

1. Glass: - Density of glass, ρ = 2.5 g/cm³. - Using the formula, F = ρ * V * g, we can calculate the Archimedes' force for glass.

2. Aluminum: - Density of aluminum, ρ = 2.7 g/cm³. - Using the formula, F = ρ * V * g, we can calculate the Archimedes' force for aluminum.

3. Lead: - Density of lead, ρ = 11.3 g/cm³. - Using the formula, F = ρ * V * g, we can calculate the Archimedes' force for lead.

Calculation Results

1. Glass: - F = 2.5 g/cm³ * 125 cm³ * 9.81 m/s² = 3061.875 N.

2. Aluminum: - F = 2.7 g/cm³ * 125 cm³ * 9.81 m/s² = 3326.625 N.

3. Lead: - F = 11.3 g/cm³ * 125 cm³ * 9.81 m/s² = 13868.125 N.

So, the Archimedes' force acting on a 125 cm³ object in water is approximately: - 3061.875 N for glass, - 3326.625 N for aluminum, and - 13868.125 N for lead.