Question

В мензурку с водой поместили не тонущее в воде тело.Уровень воды в мензурке при этом поднялся от деления 100мл до деления 200мл. Определите вес тела.

Answer 1

Сила тяготения минус сила Архимеда равно

Answer 2

Calculating the Weight of the Object in Water

To calculate the weight of the object in water, we can use the principle of buoyancy. When an object is submerged in water, it experiences an upward buoyant force equal to the weight of the water it displaces. This force reduces the apparent weight of the object in water.

Given: - The water level in the measuring cylinder rose from the 100ml mark to the 200ml mark when the object was submerged.

We can use the following formula to calculate the weight of the object in water:

Weight of the object in water = Weight of the object - Weight of the water displaced

Calculation

Using the provided information, we can calculate the weight of the object in water.

The weight of the water displaced can be calculated by finding the difference in volume before and after submerging the object.

Volume of water displaced = Final volume - Initial volume

Volume of water displaced = 200ml - 100ml = 100ml

Now, we can convert the volume of water displaced to its weight using the density of water.

Density of Water

The density of water is approximately 1 gram per milliliter.

Weight of water displaced = Volume of water displaced * Density of water

Weight of water displaced = 100ml * 1g/ml = 100g

Now, we can use the weight of the water displaced to calculate the weight of the object in water.

Weight of the object in water = Weight of the object - Weight of water displaced

Conclusion

By using the principle of buoyancy and the provided information, we can calculate the weight of the object in water.