Question

Какое количество энергии выделит вода массой 5 кг при охлаждении от 100 до 0 градусов?

Answer 1

 Q=cm(tк-tн)

1) 100-0=100 градусов - средняя темперотура воды

2) 4200*100*5= 2100000 ( Дж )

Ответ: 2100000 Дж 

Answer 2

Energy Released by Cooling Water

To calculate the energy released by cooling water from 100 to 0 degrees Celsius, we can use the formula:

Q = mcΔT

Where: - Q = energy released - m = mass of water - c = specific heat capacity of water - ΔT = change in temperature

Given: - m = 5 kg - ΔT = 100 - 0 = 100°C

We also need to consider the latent heat of vaporization, L, when the water reaches 100°C.

Using the specific heat capacity of water, c = 4.18 J/g°C, and the latent heat of vaporization of water, L = 2.26 × 10^6 J/kg, we can calculate the energy released.

Calculation

1. Energy released due to temperature change: - Q1 = mcΔT - Q1 = 5 kg × 4.18 J/g°C × 100°C [[7 #]]

2. Energy released due to phase change at 100°C: - Q2 = mL - Q2 = 5 kg × 2.26 × 10^6 J/kg [[7 #]]

3. Total energy released: - Q = Q1 + Q2

Result

The total energy released by cooling 5 kg of water from 100 to 0 degrees Celsius is the sum of Q1 and Q2.

Therefore, the total energy released is the sum of Q1 and Q2.

Answer

The total energy released by cooling 5 kg of water from 100 to 0 degrees Celsius is the sum of Q1 and Q2, which are calculated as follows: - Q1 = 5 kg × 4.18 J/g°C × 100°C - Q2 = 5 kg × 2.26 × 10^6 J/kg