Question

Луч падает из плотной среды с показателем преломления n=1.6 на границу с воздухом. В воздухе его направление отличается от направления в среде на 30 градусов. Найти угол падения.

Answer 1

Надо использовать закон преломления

sinA/sinB=n1/n2

подставляем:

sinA=sinB*n2/n1=0.8

угол равен 54 градуса

Answer 2

Finding the Angle of Incidence

To find the angle of incidence when a light ray passes from a dense medium with a refractive index of 1.6 to air, and the direction of the ray in air is different from the direction in the medium by 30 degrees, we can use the laws of refraction.

The law of refraction states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the ratio of the refractive indices of the two media. Mathematically, this can be expressed as:

sin(θ1) / sin(θ2) = n2 / n1

Where: - θ1 is the angle of incidence - θ2 is the angle of refraction - n1 is the refractive index of the initial medium (dense medium) - n2 is the refractive index of the final medium (air)

In this case, the refractive index of the dense medium is 1.6, and the refractive index of air is approximately 1.

Let's solve for the angle of incidence (θ1):

sin(θ1) / sin(30) = 1 / 1.6

To find the value of θ1, we can rearrange the equation:

sin(θ1) = (sin(30) / 1.6)

Taking the inverse sine of both sides:

θ1 = arcsin(sin(30) / 1.6)

Using a calculator, we can find the value of θ1 to be approximately 18.19 degrees.

Therefore, the angle of incidence is approximately 18.19 degrees.