Question

Под каким углом к горизонту вылетел снаряд из ствола с начальной скоростью 600м/с,если его масса равна 3 кг,а кинетическая энергия в высшей точке траектории 270кДж.Чему равна потенциальная энергия в этой точке? Сопротивлением пренебречь.

Answer 1

V0= 600 м/с
m = 3кг
Ek= 270кДж
кинетическая энергия в высшей точке траектории Ek= 270кДж 270 000 Дж
Ek = mV^2/2
V = √ (Ek/m)
в высшей точке траектории 
Vx = V
Vx = √ (Ek/m)
Под каким углом <a  к горизонту вылетел снаряд из ствола
cos<a = Vx/V0  = √ (Ek/m) / V0 =√ (270000/3)  / 600 = 0.5 = 1/2 = cos 60 
<a = 60 град
полная энергия при вылете из ствола
E =  Ek0 = mV0^2/2
в высшей точке траектории потенциальная энергия  
Eп = Е - Еk =mV0^2/2 - Ek =  3*600^2/2 - 270000= 270 000 Дж = 270 кДж
*** потенциальную энергию можно посчитать через высоту по ф-ле Еп =mgh

Answer 2

Calculating the Angle and Potential Energy of the Projectile

To calculate the angle at which the projectile was launched and the potential energy at the highest point of its trajectory, we can use the given initial velocity, mass of the projectile, and kinetic energy at the highest point.

Given: - Initial velocity (u) = 600 m/s - Mass (m) = 3 kg - Kinetic energy at the highest point = 270 kJ

First, let's calculate the angle at which the projectile was launched using the initial velocity and mass of the projectile.

The formula to calculate the angle at which the projectile was launched is: θ = arctan((v^2 ± √(v^4 - g(gx^2 + 2yv^2)))/(gx))

Where: - θ = angle of launch - v = initial velocity - g = acceleration due to gravity - x = horizontal distance - y = vertical distance

Using the given values, we can calculate the angle at which the projectile was launched.

Next, let's calculate the potential energy at the highest point of the trajectory.

The formula to calculate potential energy is: Potential Energy = mass * acceleration due to gravity * height

We can use the given mass of the projectile and the acceleration due to gravity to calculate the potential energy at the highest point of the trajectory.

Let's proceed with the calculations.