Question

Поезд идет со скоростью 20 метров секунду чему будет равна скорость поезда после торможения происходящего с ускорением 0,25 метров секунду в квадрате

Answer 1

Дано:                                Решение:
U(0)-20 м/с                         U-U0at
t-20 с                                 20-0.25*20
о-20м/с                              20-5=15 м /с
найти
u-?

Answer 2

Calculating the Final Velocity of the Train After Braking

To calculate the final velocity of the train after braking, we can use the following equation of motion:

v^2 = u^2 + 2as

Where: - v = final velocity - u = initial velocity - a = acceleration - s = distance

Given: - Initial velocity (u) = 20 m/s - Acceleration (a) = -0.25 m/s^2 (negative because it's deceleration) - We need to find the final velocity (v)

Using the equation of motion, we can calculate the final velocity of the train after braking.

Calculation

Using the equation v^2 = u^2 + 2as, where u = 20 m/s and a = -0.25 m/s^2: ``` v^2 = (20 m/s)^2 + 2*(-0.25 m/s^2)*s ```

As the distance (s) is not provided, we cannot calculate the exact final velocity without this information. If you have the distance the train travels during braking, please provide it, and I can calculate the final velocity using the given acceleration.

If you have any further questions or need additional assistance, feel free to ask!