Question

Конденсатор, ємність якого C1=2мкФ, заряджають до напруги U1=110B. Потім відєднавши від мережі, його замикають на конденсатор, ємність якого С2 - невідома. Визначити ємність конденсатора С2, якщо він заряджається до напруги U2=44B

Answer 1

Дано C1=2мкФ   U1=110В     U=44 В   C2- ?


по закону сохранения зарядов

Q=Q1=Q2

C1*U1=C1U+C2U

C2=C1(U1-U)\U=2*66\44=2*6\4=3 мкФ

Ответ C2=3 мкФ

Answer 2

Capacitor Charging and Discharging Calculation

To determine the capacitance of capacitor C2 when it is charged to a voltage of U2=44V after being disconnected from the network, we can use the formula for the charge on a capacitor:

Q = C * V

Where: - Q is the charge on the capacitor - C is the capacitance of the capacitor - V is the voltage across the capacitor

When the capacitor C1 is charged to a voltage of U1=110V, the charge on it can be calculated using the same formula.

Calculation Steps

1. Calculate the charge on capacitor C1: - Using the formula Q = C * V, where C = 2μF and V = 110V, we can calculate the charge on capacitor C1.

2. Calculate the charge on capacitor C2: - Since the charge on a capacitor is the same when connected in parallel, the charge on capacitor C2 will be the same as the charge on capacitor C1.

3. Calculate the capacitance of capacitor C2: - Using the formula Q = C * V and the known values of charge (from step 2) and voltage (U2=44V), we can solve for the capacitance C2.

Calculation

1. Calculate the charge on capacitor C1: - Q1 = C1 * U1 - Q1 = 2μF * 110V - Q1 = 220μC

2. Calculate the charge on capacitor C2: - Since the charge on capacitor C2 will be the same as on C1, Q2 = 220μC

3. Calculate the capacitance of capacitor C2: - Using the formula Q = C * V, we can solve for C2: - Q2 = C2 * U2 - 220μC = C2 * 44V - C2 = 220μC / 44V - C2 = 5μF

Conclusion

The capacitance of capacitor C2 is 5μF when it is charged to a voltage of U2=44V after being disconnected from the network.