
Капли дождя при скорости ветра v1=11 м/с падают под углом α=30 градусов к вертикали. При какой
скорости ветра v2 капли будут падать под углом β=45 градусов?

Ответы на вопрос

Ответ: 19,053 м/с.




Calculation of the Velocity of Raindrops at Angle β
To calculate the velocity of raindrops at angle β, we can use the given information about the velocity of raindrops at angle α and the angle between the vertical and the direction of motion of raindrops.
Given: - Velocity of raindrops at angle α (v1) = 11 m/s - Angle between the vertical and the direction of motion of raindrops at angle α (α) = 30 degrees - Angle between the vertical and the direction of motion of raindrops at angle β (β) = 45 degrees
We need to find the velocity of raindrops at angle β (v2).
To solve this problem, we can use the principle of conservation of energy. The kinetic energy of the raindrops at angle α should be equal to the kinetic energy of the raindrops at angle β.
The kinetic energy of an object can be calculated using the formula:
Kinetic Energy = (1/2) * mass * velocity^2
Since the mass of the raindrops is the same, we can equate the kinetic energies at angles α and β:
(1/2) * mass * v1^2 = (1/2) * mass * v2^2
Simplifying the equation, we get:
v1^2 = v2^2
Taking the square root of both sides, we find:
v1 = v2
Therefore, the velocity of the raindrops at angle β (v2) is equal to the velocity of the raindrops at angle α (v1), which is 11 m/s.
So, the raindrops will fall at angle β = 45 degrees with a velocity of v2 = 11 m/s.
Please note that the above calculation assumes ideal conditions and neglects factors such as air resistance, which may affect the actual behavior of raindrops.


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