Question

Частота обертання повітряного гвинта літака 1500 об/хв. Скільки обертів робить гвинт на шляху 90 км при швидкості 360 км/год.

Answer 1

360*1000=360000м/год/60=6000м/хв
90000/6000=15*1500=22500- обертів зробить гвинт

Answer 2

Calculation of the Number of Revolutions

To calculate the number of revolutions made by the propeller on a 90 km journey at a speed of 360 km/h, we need to consider the relationship between the speed of the aircraft, the distance traveled, and the rotation speed of the propeller.

The formula to calculate the number of revolutions is:

Number of Revolutions = (Distance Traveled / Circumference of Propeller Path) * 60

Where: - Distance Traveled is given as 90 km. - Circumference of Propeller Path is calculated using the formula: Circumference = 2 * π * Radius. - The radius of the propeller path is calculated using the formula: Radius = Speed of Propeller / (2 * π * Rotation Speed).

Let's calculate the number of revolutions using the given values:

1. Convert the speed of the aircraft from km/h to m/s: - Speed of the aircraft = 360 km/h = 360,000 m/3600 s = 100 m/s.

2. Convert the rotation speed of the propeller from revolutions per minute (rpm) to revolutions per second (rps): - Rotation speed of the propeller = 1500 rpm = 1500 / 60 = 25 rps.

3. Calculate the radius of the propeller path: - Radius = Speed of Propeller / (2 * π * Rotation Speed) = 100 m/s / (2 * π * 25 rps) = 0.6366 m.

4. Calculate the circumference of the propeller path: - Circumference = 2 * π * Radius = 2 * π * 0.6366 m = 4 m.

5. Calculate the number of revolutions: - Number of Revolutions = (Distance Traveled / Circumference of Propeller Path) * 60 = (90 km / 4 m) * 60 = 1350 revolutions.

Therefore, the propeller makes approximately 1350 revolutions on a 90 km journey at a speed of 360 km/h.

Please note that the calculations provided are based on the given information and assumptions.