Question

у подножия горы барометр показывает 98 642 Па, а на ее вершине 90 917 Па .Определите высоту горы.и вот еще ртутный барометр уронили,и он,сохраняя вертикальное положение,падает с большой высоты.Если не учитывать сопротивление воздуха ,томожно считать ,что барометр при падении находится в состоянии невесомости.что он будет показывать?

Answer 1

P=P1-P2.P=pg(h2-h1). h2=(P1-P2)/gp=8325/(10*1.2)=693.75(м).Все зависит от плотности воздуха.Ответ 693.75 м

Answer 2

Determining the Height of the Mountain

To determine the height of the mountain, we can use the difference in atmospheric pressure between the base and the summit. The atmospheric pressure decreases with increasing altitude.

Given that the barometer at the base of the mountain shows a pressure of 98,642 Pa and the barometer at the summit shows a pressure of 90,917 Pa, we can calculate the height of the mountain using the relationship between pressure and altitude.

The relationship between pressure and altitude can be approximated using the barometric formula, which states that the pressure at a given altitude is proportional to the exponential of the negative ratio of the altitude to the scale height. The scale height is a constant that depends on the properties of the atmosphere.

Using the barometric formula, we can calculate the height of the mountain as follows:

1. Calculate the pressure difference between the base and the summit: ``` pressure difference = pressure at the base - pressure at the summit = 98,642 Pa - 90,917 Pa = 7,725 Pa ```

2. Calculate the scale height: The scale height can vary depending on atmospheric conditions, but a typical value is around 8,400 meters.

3. Calculate the height of the mountain: ``` height = (pressure difference) * (scale height) / (pressure at the base) = 7,725 Pa * 8,400 m / 98,642 Pa ≈ 659.4 meters ```

Therefore, the height of the mountain is approximately 659.4 meters.

Barometer in Free Fall

If a mercury barometer is dropped from a great height, neglecting air resistance, it will be in a state of weightlessness during the fall. In this case, the barometer will not show any pressure reading.

When an object is in free fall, it experiences zero gravity, and all objects inside it, including the mercury in the barometer, will be in a state of weightlessness. As a result, the mercury column inside the barometer will not be affected by gravity and will not indicate any pressure.

Therefore, if the mercury barometer is dropped from a great height and we neglect air resistance, it will not show any pressure reading.