
Два одинаковых медных шара получили одинаковую энергию, в результате чего первый шар нагрелся,
оставаясь неподвижным, на 40 градусов, а второй приобрел некоторую скорость, не нагреваясь. определите эту скорость.очень надо, поподробнее, пожалуйста)

Ответы на вопрос




Problem Analysis
We have two identical copper spheres that receive the same amount of energy. As a result, one sphere heats up while remaining stationary, and the other sphere acquires some velocity without heating up. We need to determine the velocity acquired by the second sphere.Solution
To solve this problem, we can use the principle of conservation of energy. The energy given to the spheres is converted into two forms: thermal energy (which causes the temperature increase) and kinetic energy (which causes the velocity increase). Since the spheres receive the same amount of energy, we can equate the changes in thermal and kinetic energy.Let's assume the mass of each sphere is m and the specific heat capacity of copper is c. The change in thermal energy can be calculated using the formula:
ΔQ = mcΔT
where ΔQ is the change in thermal energy, ΔT is the change in temperature, and c is the specific heat capacity.
The change in kinetic energy can be calculated using the formula:
ΔK = 0.5mv^2
where ΔK is the change in kinetic energy and v is the velocity acquired by the second sphere.
Since the spheres receive the same amount of energy, we can equate the changes in thermal and kinetic energy:
mcΔT = 0.5mv^2
Simplifying the equation, we can cancel out the mass m:
cΔT = 0.5v^2
Now we can solve for v:
v = sqrt(2cΔT)
Substituting the given values, where ΔT = 40 degrees Celsius and the specific heat capacity of copper is approximately 0.385 J/g°C we can calculate the velocity v.
Calculation
Using the formula v = sqrt(2cΔT) and substituting the values:v = sqrt(2 * 0.385 J/g°C * 40°C)
v ≈ sqrt(30.8 J/g)
v ≈ 5.54 m/s
Therefore, the velocity acquired by the second sphere is approximately 5.54 m/s.
Answer
The velocity acquired by the second sphere, without heating up, is approximately 5.54 m/s.Please let me know if you need any further clarification.


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