Question

Какое количество теплоты выделиться за 30 мин проволочной спиралью сопротивлением 20 ом при силе тока 5а

Answer 1

Q=I²*R*t=5²*20*(30*60)=900000 Дж   (0,9 МДж)

Answer 2

Calculation of Heat Generated by a Wire Coil

To calculate the amount of heat generated by a wire coil, we can use the formula:

Q = I^2 * R * t

Where: - Q is the amount of heat generated (in joules) - I is the current flowing through the wire (in amperes) - R is the resistance of the wire (in ohms) - t is the time for which the current flows (in seconds)

In this case, we are given the following values: - Resistance (R) = 20 ohms - Current (I) = 5 amperes - Time (t) = 30 minutes = 30 * 60 seconds = 1800 seconds

Let's substitute these values into the formula and calculate the heat generated:

Q = (5^2) * 20 * 1800

Simplifying the equation:

Q = 25 * 20 * 1800

Q = 900,000 joules

Therefore, the amount of heat generated by the wire coil in 30 minutes is 900,000 joules.