Question

1. Лампочка с сопротивлением 400 Ом включена в цепь с напряжением 220 В. Какую работу совершает ток, протекающий по лампочке за 40 мин.

Answer 1

R-4000 m

U-220B

t=40 мин

Найти:

A-?

Решение:

A-ult

I-U/R

I=220b/4000m=0,55A

A=220B*0, 555A*2400c-290400дж

Answer 2

Calculation of Work Done by Current

To calculate the work done by the current flowing through the light bulb, we need to use the formula:

Work (W) = Power (P) x Time (t)

The power (P) can be calculated using the formula:

Power (P) = (Current (I))^2 x Resistance (R)

Given: - Resistance of the light bulb (R) = 400 Ω - Voltage across the light bulb (V) = 220 V - Time (t) = 40 minutes

To find the current (I), we can use Ohm's Law:

Current (I) = Voltage (V) / Resistance (R)

Let's calculate the current first:

Current (I) = 220 V / 400 Ω

Using a calculator, we find that the current is approximately 0.55 A.

Now, let's calculate the power:

Power (P) = (0.55 A)^2 x 400 Ω

Using a calculator, we find that the power is approximately 121 W.

Finally, we can calculate the work done:

Work (W) = Power (P) x Time (t)

Work (W) = 121 W x 40 minutes

Note: We need to convert the time from minutes to seconds to match the unit of power.

Work (W) = 121 W x (40 minutes x 60 seconds/minute)

Using a calculator, we find that the work done by the current flowing through the light bulb for 40 minutes is approximately 290,400 Joules.

Therefore, the work done by the current flowing through the light bulb for 40 minutes is approximately 290,400 Joules.