Question

На рычаг действуют две силы, плечи которых равны 20 см и 40 см. Сила, действующая на короткое плечо, равна 6Н. Чему должна быть равна сила, действующая на длинное плечо чтобы рычаг был в равновесии???7 с дано

Answer 1

F1=6H
l1=0.2м
l2=0.4м
F2=?
F1l1=F2l2
F2=F1l1/l2
F2=6*0.2/0.4=3H
Ответ:3Н

Answer 2

Calculation of the Force on the Long Arm of the Lever

To determine the force required to balance the lever, we can use the principle of moments. The principle of moments states that for an object to be in equilibrium, the sum of the clockwise moments must be equal to the sum of the counterclockwise moments.

In this case, we have two forces acting on the lever: one force on the short arm and another force on the long arm. The lengths of the short and long arms are given as 20 cm and 40 cm, respectively. The force on the short arm is given as 6 N.

Let's denote the force on the long arm as F. The moment of the force on the short arm can be calculated as the product of the force and the length of the short arm:

Moment of force on short arm = Force on short arm × Length of short arm = 6 N × 20 cm

The moment of the force on the long arm can be calculated as the product of the force and the length of the long arm:

Moment of force on long arm = Force on long arm × Length of long arm = F × 40 cm

Since the lever is in equilibrium, the sum of the clockwise moments must be equal to the sum of the counterclockwise moments. Therefore, we can set up the following equation:

Moment of force on short arm = Moment of force on long arm

Substituting the given values, we have:

6 N × 20 cm = F × 40 cm

Simplifying the equation, we can cancel out the units of length:

6 N × 20 = F × 40

Now we can solve for F:

F = (6 N × 20) / 40

Calculating the value, we find:

F = 3 N

Therefore, the force required to balance the lever on the long arm should be 3 N.