Question

Кал двигателя 25% и развивает полезную мощность 27кВт.определите количество бензина сдвигаемого в цилиндрах за 1 час

Answer 1

Дано:
ŋ = 0,25
N п = 27 000 Вт
t = 3600 с
q = 46 МДж/кг
Найти: m - ?
Решение:
ŋ = N п/N з
ŋ = N п/(mq/t)
mq/t = N п/ŋ
mq = N п × t/ŋ
m = N п × t/ŋq
m = 27 000 Вт × 3600 с/0,25 × 46 000 000 Дж/кг ≈ 8,5 кг

Answer 2

Calculation of Fuel Consumption

To determine the amount of gasoline consumed by the engine in one hour, we can use the following formula:

Fuel consumption (in liters per hour) = Power output (in kilowatts) / Efficiency of the engine (in liters per kilowatt-hour)

Given: - Power output = 27 kW - Efficiency of the engine = 25%

Using the formula, we can calculate the fuel consumption:

Fuel consumption = 27 kW / 25%

Now, let's calculate the fuel consumption.