Question

В гидравлическом прессе площадь большого поршня 300 см (в квадрате 2) площадь маленького поршня-30см.На малый поршень действует сила, модуль которой равен 500Н. Найдите модуль силы действующей на большой поршень.Трение не учитывать. ПОМОГИТЕ СРОЧНО НУЖНО!!!

Answer 1

S1=300 см²
S2=30см²
F2= 500Н
F1-  ?   
 F1/S1=F2/S2, F1=F2S1/S2,
F1=500*300/30=5000 Н.

Answer 2

Calculating Force on the Large Piston in a Hydraulic Press

To calculate the force acting on the large piston in a hydraulic press, we can use the principle of Pascal's law, which states that the pressure applied to a fluid is transmitted undiminished through the fluid in all directions.

Given: - Area of the large piston (A1) = 300 cm^2 - Area of the small piston (A2) = 30 cm^2 - Force applied on the small piston (F2) = 500 N

Using the formula: F1 = F2 * (A1 / A2)

Where: - F1 = Force on the large piston - F2 = Force on the small piston - A1 = Area of the large piston - A2 = Area of the small piston

Calculating the Force

Using the given values: F1 = 500 N * (300 cm^2 / 30 cm^2)

Calculating the force: F1 = 500 N * 10 F1 = 5000 N

Therefore, the force acting on the large piston in the hydraulic press is 5000 N.