Question

Полый шар 500 грамм всплывает в воде. С каким ускорение двигался шар, если сила сопротивления 3Н (Ньютона), а архимедова 12Н (Ньютона)

Answer 1

Дано
m=500 g=0,5 kg
Fс=3 Н
Fар =12 Н
a=?
Решение;
СуммаF=Fар-Fс-mg=12-3-0,5*10=4 H
a=суммаF/m=4/0,5=8м/с^2
Ответ: 8м/с^2

Answer 2

Calculation of the Acceleration of the Ball

To calculate the acceleration of the ball, we need to consider the forces acting on it: the buoyant force and the resistance force.

The buoyant force, also known as the Archimedes' principle, is equal to the weight of the fluid displaced by the object. In this case, the buoyant force is given as 12 N (Newtons).

The resistance force, also known as the drag force, opposes the motion of the ball through the fluid. It is given as 3 N (Newtons).

The net force acting on the ball is the difference between the buoyant force and the resistance force:

Net force = Buoyant force - Resistance force

To find the acceleration, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration:

Net force = mass * acceleration

By equating the two equations above, we can solve for the acceleration:

Buoyant force - Resistance force = mass * acceleration

Substituting the given values:

12 N - 3 N = 0.5 kg * acceleration

Simplifying the equation:

9 N = 0.5 kg * acceleration

Solving for acceleration:

acceleration = 9 N / 0.5 kg = 18 m/s^2

Therefore, the ball was moving with an acceleration of 18 m/s^2.

Please note that the given information does not specify the mass of the ball, so we assumed a mass of 0.5 kg for the calculation.