Question

Под каким давлением находиться воздух в воздушном пузырьке диаметром 1 мм в воде на глубине 80 см если атмосферное давление нормальное

Answer 1

P=ρgh
Плотность воды = 1000 кг/м³
p=1000*10*0,8=8000 Па 
Плюс атмосферное давление. Если оно нормальное, то оно равно  101308 Па.
Итого общее давление, действующее на воздух - 109308 Па или 109,308 кПа

Answer 2

Air Pressure in a Bubble in Water

To determine the pressure inside an air bubble with a diameter of 1 mm in water at a depth of 80 cm, we need to consider the atmospheric pressure and the hydrostatic pressure exerted by the water column.

The atmospheric pressure at sea level is approximately 101.325 kilopascals (kPa) or 1 atmosphere (atm) This is considered the normal atmospheric pressure.

The hydrostatic pressure exerted by a fluid, such as water, increases with depth. The pressure increases by approximately 9.8 kilopascals (kPa) for every meter of depth Therefore, at a depth of 80 cm (or 0.8 meters), the hydrostatic pressure would be approximately 0.8 * 9.8 = 7.84 kilopascals (kPa).

To calculate the total pressure inside the air bubble, we need to add the atmospheric pressure and the hydrostatic pressure:

Total pressure = Atmospheric pressure + Hydrostatic pressure

Total pressure = 101.325 kPa + 7.84 kPa

Total pressure = 109.165 kPa

Therefore, the air pressure inside the air bubble with a diameter of 1 mm in water at a depth of 80 cm is approximately 109.165 kilopascals (kPa).

Please note that this calculation assumes ideal conditions and does not take into account other factors such as temperature or the presence of dissolved gases in the water.

I hope this helps! Let me know if you have any further questions.