Question

Под действием силы 5Hпружина удлинилась на 2см.Определите массу тела под действием которого пружина удлинилась на 5см .

Answer 1

F = k*x
k=F/x
2см = 0.02м
k= 5(Н)/0.02(м) = 250 Н/м
F = 250(Н/м)*0.05(м) = 12,5 Н
F =mg
m = F/g = 12.5 / 10 = 1.25 кг

Answer 2

Calculation of the mass of the body

To determine the mass of the body that caused the spring to elongate by 5 cm, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.

Hooke's Law can be expressed as:

F = kx

Where: - F is the force exerted by the spring, - k is the spring constant, - x is the displacement of the spring from its equilibrium position.

In this case, we know that the spring elongated by 2 cm under a force of 5 H. We need to find the mass of the body that caused the spring to elongate by 5 cm.

Let's break down the problem step by step:

1. We know that the spring elongated by 2 cm under a force of 5 H. From this information, we can determine the spring constant (k) using Hooke's Law.

2. Once we have the spring constant, we can calculate the force exerted by the spring when it elongates by 5 cm.

3. Finally, we can use the formula for gravitational force to calculate the mass of the body that caused the spring to elongate by 5 cm.

Let's calculate the mass of the body using the given information.

Step 1: Calculating the spring constant (k)

From the given information, we know that the spring elongated by 2 cm under a force of 5 H. Using Hooke's Law, we can calculate the spring constant (k).

F = kx

Substituting the values: 5 H = k * 2 cm

Converting cm to meters: 5 H = k * 0.02 m

Simplifying the equation: k = 5 H / 0.02 m

Calculating the value of k: k = 250 H/m

Step 2: Calculating the force exerted by the spring

Now that we have the spring constant (k), we can calculate the force exerted by the spring when it elongates by 5 cm.

F = kx

Substituting the values: F = 250 H/m * 0.05 m

Simplifying the equation: F = 12.5 H

The force exerted by the spring when it elongates by 5 cm is 12.5 H.

Step 3: Calculating the mass of the body

To calculate the mass of the body that caused the spring to elongate by 5 cm, we can use the formula for gravitational force:

F = mg

Where: - F is the force exerted by the spring (12.5 H), - m is the mass of the body, - g is the acceleration due to gravity (approximately 9.8 m/s^2).

Substituting the values: 12.5 H = m * 9.8 m/s^2

Simplifying the equation: m = 12.5 H / 9.8 m/s^2

Calculating the value of m: m ≈ 1.28 kg

Therefore, the mass of the body that caused the spring to elongate by 5 cm is approximately 1.28 kg.

Please note that the calculations provided are based on the given information and assumptions.