Question

Температура латунной детали массой 2 кг равна 365 градусов .Какое количество теплоты она передаст окружающим телам при охлаждении до 15 градусов ?

Answer 1

Q = c * m * (t2 - t1) = 0,377 * 2 * (365 - 15) = 263,9 Дж

Answer 2

Calculation of Heat Transfer

To calculate the amount of heat transferred by a brass object when it cools from 365 degrees Celsius to 15 degrees Celsius, we can use the formula:

Q = mcΔT

Where: - Q is the amount of heat transferred - m is the mass of the object - c is the specific heat capacity of the material - ΔT is the change in temperature

In this case, the mass of the brass object is 2 kg and the change in temperature is 365 - 15 = 350 degrees Celsius.

Now, we need to find the specific heat capacity of brass. Unfortunately, the search results did not provide a direct answer to the specific heat capacity of brass. However, we can assume that the specific heat capacity of brass is similar to that of copper, as they have similar properties. The specific heat capacity of copper is approximately 0.385 J/g°C.

Converting the mass of the brass object from kg to grams, we have:

m = 2 kg = 2000 g

Substituting the values into the formula, we get:

Q = (2000 g) * (0.385 J/g°C) * (350°C) = 269,500 J

Therefore, the brass object will transfer approximately 269,500 joules of heat to the surrounding bodies during the cooling process.

Please note that the specific heat capacity of brass may vary slightly depending on the composition of the alloy and impurities present. However, the assumed value of 0.385 J/g°C for copper should provide a reasonable estimate for brass as well.

I hope this helps! Let me know if you have any further questions.