Question

Ракета масса которой вместе с зарядом составляет 250 г взлетает вертикально вверх и достигает высоты h=150м . Определите скорость истечения газов из ракеты, считая что загорание заряда происходит мгновенно , масса заряда равна 50 г.

Answer 1

Данная задача на закон сохранения импульса + закон сохранения энергии.
Закон сохранения импульса:
$m_{r}*v_{r}=m_{g}*v_{g}$

Закон сохранения энергии:
$\frac{m_{r}*(v_{r})^2}{2} =m_{r}*g*h$

Здесь масса ракеты - 200 г

Answer 2

Calculation of the Exhaust Gas Velocity

To determine the exhaust gas velocity of the rocket, we can use the principle of conservation of momentum. The momentum before the rocket is launched is equal to the momentum after the rocket is launched.

The momentum of the rocket before launch is given by:

momentum_before = (mass_rocket + mass_charge) * velocity_before

The momentum of the rocket after launch is given by:

momentum_after = mass_rocket * velocity_after

Since the rocket is launched vertically upwards, the velocity before launch is zero. Therefore, the momentum before launch is also zero.

Setting the momentum before launch equal to the momentum after launch, we have:

(mass_rocket + mass_charge) * velocity_before = mass_rocket * velocity_after

Rearranging the equation to solve for the exhaust gas velocity, we get:

velocity_after = (mass_rocket + mass_charge) * velocity_before / mass_rocket

Given that the mass of the rocket (including the charge) is 250 g and the mass of the charge is 50 g, we can substitute these values into the equation. Additionally, since the rocket is launched vertically upwards, the velocity before launch is zero.

Let's calculate the exhaust gas velocity.